2 murderers, 2 sherrifs, little more Innocents, basically everything 2 times more, even coins required, to get a bow as innocent.
Not sure, what you think about the time limit.
It would require, to make bigger maps tho.
Two murders and two sheriffs sure, but keep the innocent count the same.
Wouldn’t that be too easy for murderers?
As it is, it’s way too hard to win as a murderer when compared to an innocent. In my opinion, it’ll just be more balanced.
And a double trouble gamemode should definitely be more fast-paced. Like is it really double trouble or just double, if it’s the same proportions of murderers and innocents.
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Appreciate your opinion! Thanks for replying and have a good day
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This idea has already been suggested, however I’ll give ya a vote. Also
If you have double mur and you keep the innocents the same… u do realize how sided that would be towards the mur… you’re right though, it shouldn’t be a 1:15 ratio when doubling, however, it should def be around 22-25 innos imo to keep it fair
Also, same time limit as you have 2x mur so theoretically their shouldn’t be any issues with killing everyone in the same amount of time as 1x
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Bigger maps could be the limit
I agree that the innocent number should be the same- It would be too hard to win for sherrif, but the innocents could be little more, so murderers wouldn’t win that easily
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Agree to disagree i guess, I think if you’ve played double MM, your opinion would change, but that’s just me.
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Do you understand how infrequently the murderer wins? This would probably be way more balanced than the normal game. Also remember there are two sheriffs in my suggestion.
Sheriffs already can’t shoot eachother (as in, literally nothing will happen if you try). I’ve already tested that in a cs. The innocent count deserves to stay the same.
if a member of a party is chosen as murd can we make it so that another member of that party gets picked to be murd with the original person